Calculate drop-out delay of a relay
Relays are used everywhere today. They've gotten smaller and more efficient in recent years, but they still have a certain lag time.
This is hidden behind a relay
- A relay is nothing more than a switch that is actuated electromagnetically. One current causes the relay to switch another current. There are usually two switch positions: on and off.
- The structure can be explained schematically in such a way that there is a metallic core in a coil. An anchor is located at a small distance from the top or bottom of the core. If a current flows through the coil, a magnetic field is induced in the core.
- The magnetic field attracts the armature and another current circuit is thereby closed. When the magnetic field is gone, a spring moves the armature back to its original position. The circuit is no longer closed.
This is the fall delay
- If you remove the control voltage to switch off the circuit, then the relay tries to counteract the drop in the control voltage and the magnetic field is maintained for a short time. For you, this means that you can only switch off the second circuit with a slight delay - with the drop-out delay.
- You should also expect that the magnetic field will be induced with a slight delay when you switch it on. So it takes a very short time for the second circuit to turn off when the relay is closed.
- This delay in turning the relay off is called the drop-out delay, which is the delay that occurs when the voltage drops.
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How to calculate the release delay of a relay
- Connect a meter to the second circuit.
- Connect this to a clock that can be controlled by voltage.
- The switching voltages are the relay and the control voltage. The measured difference in time between the two voltages is the drop-out delay.
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