Use the physics formula correctly for kinetic energy

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In principle, the formula for the kinetic energy can be found in any collection of formulas. But how is it properly applied to a physical problem?

All bodies fall at the same speed.
All bodies fall at the same speed.

What you need:

  • Basic knowledge of "mechanics"

Formula for kinetic energy - simply explained

  • Granted, formulas in mathematics and physics can be a deterrent, because they contain physical quantities or mathematical expressions in short form, i.e. as letters. However, if you know the meaning of the abbreviations, it is easy to work with the formula.
  • The formula for the kinetic energy is simply E = 1/2 m v².
  • E means the energy of the moving body or object (in the unit J for "Joule"), m is the mass (weight in everyday life called) of the body (in the unit kg for "kilogram) and v the speed with which the body moves emotional. The unit of speed is to be selected appropriately here, namely in m / s (meters per second).
  • By the way: The "kinetic energy" is also called "kinetic energy" in physics (as opposed to, for example, positional or potential energy).

Kinetic energy - two examples from physics

  • When vehicles have a certain speed, they also have kinetic energy. This is noticeable, for example, as a deformation in the event of an impact. The kinetic energy of a car (m = 900 kg) at a speed of v = 50 km / h = 13.89 m / s (conversion: 3.6!). The kinetic energy of the vehicle is E = 1/2 according to the formula * 900 kg * (13.89 m / s) ² = 86,120 J (rounded up slightly).
  • Kinetic energy in physics

    Hardly any other formula from physics is as well known as Einstein's formula ...

  • If you drop an object (for example a bar of chocolate) from a height of 1 m, it goes to This free fall converts the positional energy into kinetic energy (and is also here on impact noticeable). The speed of the chocolate on impact can be calculated from the energy balance "positional energy" = "kinetic energy". It applies to m*G*h = 1/2 mv². And further v = root (2g*h) = root (2 * 9.81 m / s² * 1 m) = 4.43 m / s. This is where Galileo's statement becomes noticeable: All bodies fall at the same speed (without air friction, of course).

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